1 solutions
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0
C :
#include "stdio.h" #include "math.h" int main() { float a = 2, b = 3, c = 1; scanf("%f,%f,%f", &a, &b, &c); if ((b * b - 4 * a * c) < 0) { printf("error!\n"); return 0; } float x1 = (-b + sqrt(b * b - 4 * a * c)) / (2 * a); float x2 = (-b - sqrt(b * b - 4 * a * c)) / (2 * a); printf("x1=%7.4f, x2=%7.4f\n", x1, x2); return 0; }
- 1
Information
- ID
- 92
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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