1 solutions
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0
C :
#include "stdio.h" #include "math.h" int main() { int n; scanf("%d", &n); if(n < 1) { // 输入的n小于等于0时,不合法 printf("error!\n"); }else if (n < 10) { printf("%d: 0-9\n", n); } else if (n < 100) { printf("%d: 10-99\n", n); } else if (n < 1000) { printf("%d: 100-999\n", n); } else if (n < 10000) { printf("%d: 1000-9999\n", n); } else { // 其余的,不合法 printf("error!\n"); } return 0; }
- 1
Information
- ID
- 91
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- (None)
- Tags
- # Submissions
- 0
- Accepted
- 0
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